The NTA (National Test Agency) published the results of JEE Main Paper 1 for April Session a day before the tentative April 30th.
The results of Paper 2 likely to be out on May 15.Breaking the trend until 2018, from this year NTA has replaced CBSE as the authority conducting JEE and the test is conducted in computer-based mode. Also JEE Mains will be conducted twice a year - in January and April.
The JEE Mains April session were held with Paper 2 on April 7 and Paper 1 on April 8, 9, 10 and 12. As per official records, over 9.35 lakh candidates had appeared for JEE Main April 2019 exam at various test centres across the nation.Candidates who qualify in JEE Main exam 2019 will be eligible to appear for JEE Advanced 2019 scheduled for June 2019. For candidates who have appeared in both January and April exam, the scores obtained in both sessions will be mentioned in the JEE Main 2019 result.
JEE Main scores are used for admissions to the B.Tech courses at top institutes like NITs, IIITs, and GFTIs and even private engineering and architecture courses.Total Mark Calculation:- Maximum score for paper 1 is 360 marks.
- Maximum score for paper 2 is 390 marks.
- Marks obtained in Paper 1 = Number of correct answers x 4 ? Number of incorrect answers x 1.
- Marks obtained in Paper 2 = Number of correct answers in Maths and Aptitude Test x 4 ? Number of incorrect answers in Maths and Aptitude Test x 1 + marks obtained in Drawing Test.
Note:- Class 12 marks are not considered for calculating normalized scores, as decided by NTA.
- For candidates to qualify for admission to IITs/ NITs/IIITs or GFTIs, should score a minimum 75% marks (65% for SC/ ST) in class 12th or be in top 20 percentile in class 12th exam.
- Only the score obtained in JEE Main 2019 will be included while releasing JEE Main Rank list name wise.
- The result of JEE Main 2019 also shows whether the candidate has qualified for JEE Advanced or not, subject to meeting other eligibility criteria.
JEE Main 2019 Cutoff - Category WiseCategory | | Total NTA Score Cutoff Based on Paper 1 |
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Common Rank List (CRL) | | 89.7548849 |
GEN-EWS | | 78.2174869 |
Other Backward Classes (OBC-NCL) | | 74.3166557 |
Scheduled Caste (SC) | | 54.0128155 |
Scheduled Tribe (ST) | | 44.3345172 |
PwD | | 0.11371730 |
Note:- National Testing Agency has released the JEE Main 2019 cutoff along with the result. Candidates can check the cutoff of JEE Main 2019 by logging into the result portal. This will be the qualifying cutoff for appearing in JEE Advanced for IIT admissions.
- JEE Main 2019 cutoff has been published separately for each category. The cutoff of JEE Main 2019 is the minimum score a candidate needs to be eligible to appear in JEE Advanced. This is not the same JEE Main cutoff that will be published by JoSAA (Joint Seat Allocation Authority) for admissions tentatively in June.
- JEE Main cutoff 2019 published by JoSAA will be specific to each branch and category in the participating NITs, IIITs and GFTIs. This cutoff of JEE Main 2019 lists the minimum ranks branch wise and category wise for admission to these institutes. JEE Main aspirants who meet the cutoff of an institute will have good chances of admission at that institute.
Click here to view your JEE Mains 2019 results.Congratulations & Best Wishes from Team ScoreExams!